-2x^2+34x-104=0

Solution for -2x^2+34x-104=0 equation:

-2x^2+34x-104=0

a = -2; b = 34; c = -104;
Δ = b2-4ac
Δ = 342-4·(-2)·(-104)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-18}{2*-2}=\frac{-52}{-4}
=+13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+18}{2*-2}=\frac{-16}{-4}
=+4
$